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添加4~10的判定
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@ -144,8 +144,16 @@ def bmcl_rank(msg: NewMessage, client: IcaClient, name: Optional[str]) -> None:
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# 如果找到 > 3 个节点, 则提示 不显示
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counts = [True for find in finds if find]
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if len(counts) > 3:
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reply = msg.reply_with(f"搜索|{name}|到{len(counts)}个节点, 请用更精确的名字")
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client.send_message(reply)
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if len(counts) > 10:
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reply = msg.reply_with(f"搜索|{name}|到{len(counts)}个节点, 请用更精确的名字")
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client.send_message(reply)
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else:
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# 4~10 个节点 只显示名称和次序
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find_msg = [f"{r['name']}-No.{i+1}" for i, r in enumerate(ranks) if finds[i]]
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find_msg = "\n".join(find_msg)
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report_msg = f"OpenBMCLAPI 面板v{_version_}-搜索|{name}|\n{find_msg}\n"
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reply = msg.reply_with(report_msg)
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client.info(report_msg)
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return
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rank_msgs = []
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for i, find in enumerate(finds):
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